Answer:
The salt is in the water be 3 lb.
Step-by-step explanation:
Formula
[tex]Percentage = \frac{Part\ value\times 100}{Total\ value}[/tex]
As given
Twenty pounds of a salt-water solution contains fifteen percent salt.
Let us assume that the salt is in the water be x.
Percentage = 15%
Total value = 20 pounds
Put in the formula
[tex]15= \frac{x\times 100}{20}[/tex]
[tex]x = \frac{15\times 20}{100}[/tex]
[tex]x = \frac{300}{100}[/tex]
x = 3 pounds
or
x = 3 lb
Therefore the salt is in the water be 3 lb.
