Respuesta :
V=(4p(3r)^3)/3 and v=(4pr^3)/3
V/v=(3r)^3/(r^3)
V/v=9r^3/r^3
V/v=9
So the smaller sphere has a volume that is nine times smaller than the larger.
V/v=(3r)^3/(r^3)
V/v=9r^3/r^3
V/v=9
So the smaller sphere has a volume that is nine times smaller than the larger.
Answer:
The volume of the smaller sphere is [tex]27[/tex] times smaller than the volume of the larger sphere
Step-by-step explanation:
we know that
If two figures are similar then, the ratio of its volumes is equal to the scale factor elevated to the cube
Let
z-------> the scale factor
x-------> the volume of the larger sphere
y-------> the volume of the smaller sphere
so
[tex]z^{3}=\frac{x}{y}[/tex]
In this problem we have
[tex]z=3[/tex]
substitute
[tex]3^{3}=\frac{x}{y}[/tex]
[tex]27=\frac{x}{y}[/tex]
[tex]y=x/27[/tex] -----> The volume of the smaller sphere is [tex]27[/tex] times smaller than the volume of the larger sphere
or
[tex]x=27y[/tex] -----> The volume of the larger sphere is [tex]27[/tex] times greater than the volume of the smaller sphere