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how do you find the g (acceleration due to gravity) in this question?

What is the period and frequency of a 10 pound weight oscilating (as a pendulum) on a 5 meter long rope?

Respuesta :

Shweta07
The weight (or mass) is irrelevant.

The period t = sqrt(2*pi*sqrt(l/g) where g is the acceleration due to gravity.

so t = 2*pi*sqrt(5/9.8) = 4.49 seconds.

Frequency = 1/period = 0.223 Hertz.
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