So [tex] 2^{ \frac{5}{2} } [/tex] is the same as [tex] \sqrt{ 2^{5} } [/tex] and therefore [tex] 2^{ \frac{3}{2} } [/tex] is [tex] \sqrt{ 2^{3} } [/tex].
So.. the [tex] \sqrt{32} [/tex] minus [tex] \sqrt{8} [/tex].
We can pull a 4 out of the 32 to make 4[tex] \sqrt{2} [/tex] as 16 times 2 is 32
We can pull a 2 out of the 8 to make 2[tex] \sqrt{2} [/tex].
Now they have like bases, so to speak, and 4-2 is 2.
So the answer is 2[tex] \sqrt{2} [/tex].
