Respuesta :
All three angles of a triangle must add up to 180°. If Angle A is 48° then 180-48=132.
Angles B and C have to add up to 132°. So we can set up an equation: (6x-28)+(2x)=132.
Drop parenthesis and combine like terms: 6x-28+2x=132
8x-28=132
Now we need to get x by itself so add 28: 8x=160
Divide by 8: x=20
Now that we now x, we can plug it in for B: 6(20)-28=92. Angle B is 92°.
Repeat for Angle C: 2(20)=40. Angle C is 40°.
To check, add all three angles together. If they equal 180, the numbers are right.
So: 48+92+40=180°.
Angles B and C have to add up to 132°. So we can set up an equation: (6x-28)+(2x)=132.
Drop parenthesis and combine like terms: 6x-28+2x=132
8x-28=132
Now we need to get x by itself so add 28: 8x=160
Divide by 8: x=20
Now that we now x, we can plug it in for B: 6(20)-28=92. Angle B is 92°.
Repeat for Angle C: 2(20)=40. Angle C is 40°.
To check, add all three angles together. If they equal 180, the numbers are right.
So: 48+92+40=180°.
Answer:
x = 20 ∠B = 92° ∠C = 40°
Step-by-step explanation:
The sum of angles of a triangle is 180°.
48 +(6x -28) +2x = 180
8x +20 = 180
8x = 160
x = 20
∠B = (6x -28)° = (6*20 -28)° = 92°
∠C = 2x° = 40°