?
A jet plane is traveling with a velocity of 720 kilometers/hour due north. There is a crosswind of 40 kilometers/hour from the east. Find the resultant velocity and the direction of the jet plane.

Respuesta :

v = 721 km/h
θ = 3.2°
Ver imagen Аноним

Answer: 721.1 km/h, at 86.6 degrees north of west

Explanation:

The magnitude of the velocity of the plane can be found by calculating the resultant of the two velocities:

[tex]R=\sqrt{(720 km/h)^2+(40 km/h)^2}=721.1 km/h[/tex]

The direction can be found as follows:

[tex]\theta = tan^{-1} (\frac{720 km/h}{40 km/h})=86.8^{\circ}[/tex]

where 720 km/h represents the velocity towards north, while 40 km/h represents the velocity towards west, so the angle is measured with respect to east. Therefore:

the direction is [tex]86.8^{\circ}[/tex] north of west

ACCESS MORE
ACCESS MORE
ACCESS MORE
ACCESS MORE