Answer:
The solubility product lead sulfate at anode is 1.69.
Explanation:
[tex]PbSO_4\rightleftharpoons Pb^{2+}+SO_4^{2-}[/tex]
S S
Concentration of sulfate ion at anode:
[tex][SO_4^{2-}]=S=1.30 M[/tex]
1 mole of lead sulfate dissociates into 1 mol of lead ion and 1 mole of sulfate ion.So.
[tex]SO_4^{2-}=[Pb^{2+}]=S[/tex]
The solubility product of the lead sulfate is:
[tex]K_{sp}=S\times S=S^2=(1.30 M)^2=1.69[/tex]
The solubility product lead sulfate at anode is 1.69.
