Respuesta :

The answer is 157kJ

formula: q=mcT

q= 75 g x 4.18 J/goC x 50 oC
q= 157 kJ

Answer:

The heat transferred is 157 kJ.

Step-by-step explanation:

Given : If 75 g of liquid water ( C = 4.18 j/g C ) in a calorimeter changes temperature from 25 C to 75 C.

To find: How much heat was transferred ?

Solution :  

Using the formula, [tex]q=mc\triangle T[/tex]

Where,

q - heat absorbed

c  - the specific heat of the substance, in your case of water

ΔT  - the change in temperature, as the difference between the final temperature and the initial temperature.

We have given,

c=4.18 j/g C

m=75 g

ΔT= 75 C-25 C=50 C

Substitute the values in the formula,

[tex]q=(75)(4.18)(50)[/tex]

[tex]q=157 kJ[/tex]

Therefore, The heat transferred is 157 kJ.

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