Respuesta :
Answer:
Final speed of the train is 7.5 m/s
Explanation:
It is given that,
Uniform acceleration of the train is, a = 1.5 m/s²
It starts from rest and travels for 5.0 s. We have to find the final velocity of the train. By using first equation of motion as :
[tex]v=u+at[/tex]
Here, train starts from rest so, u = 0
[tex]v=0+1.5\ m/s^2\times 5\ s[/tex]
v = 7.5 m/s
So, the final velocity of the train is 7.5 m/s. Hence, this is the required solution.
Answer:
[tex]7.5m/s[/tex]
Explanation:
We use the formula to find the final velocity for the movement with constant acceleration:
[tex]V_{f}=V_{i}+at[/tex]
where
[tex]V_{f}[/tex] is the final velocity of the train
[tex]V_{i}[/tex] is the initial velocity of the train, since it starts from rest [tex]V_{i}=0[/tex]
[tex]a[/tex] is the acceleration, [tex]a=1.5m/s^2[/tex]
and [tex]t[/tex] is the interval of time, [tex]t=5s[/tex]
So, replacing the values in the formula we get:
[tex]V_{f}=0+(1.5m/s^2)(5s)[/tex]
[tex]V_{f}=7.5m/s[/tex]
The final velocity of the train is [tex]7.5m/s[/tex]