Respuesta :
given that V =pi r^2 h
r = 2x + 3
h = 6x + 1
v = pi ( 2x + 3 )^2 ( 6x + 1 )
V = pi ( 4x^2 + 12x + 9 ) ( 6x + 1 )
V = pi ( 24x^3 + 4x^2 + 72x^2 + 12x + 54x + 9 )
V = pi ( 24x^3 + 76x^2 + 66x + 9 )
V = 24pix^3 + 76pix^2 + 66pix + 9pi
r = 2x + 3
h = 6x + 1
v = pi ( 2x + 3 )^2 ( 6x + 1 )
V = pi ( 4x^2 + 12x + 9 ) ( 6x + 1 )
V = pi ( 24x^3 + 4x^2 + 72x^2 + 12x + 54x + 9 )
V = pi ( 24x^3 + 76x^2 + 66x + 9 )
V = 24pix^3 + 76pix^2 + 66pix + 9pi
The polynomial for the volume of the cylinder whose radius be (2x + 3) and height be (6x + 1) is π × (24x³ + 76x² + 66x + 9 )
What is polynomial?
Polynomial is an algebraic expression that consists of variables and coefficients. Variable are called unknown. We can apply arithmetic operations such as addition, subtraction, etc. But not divisible by variable.
A cylinder has a radius of 2x + 3 and a height of 6x + 1.
The volume of the cylinder will be given as
V = πr²h
Then the polynomial for the volume of the cylinder will be
V = π × (2x + 3)² × (6x + 1)
V = π × (4x² + 12x + 9) × (6x + 1)
V = π × (24x³ + 72x² + 54x + 4x² + 12x + 9 )
V = π × (24x³ + 76x² + 66x + 9 )
More about the polynomial link is given below.
https://brainly.com/question/17822016