Answer:
Work done, [tex]W=4.65\times 10^{-15}\ J[/tex]
Explanation:
It is given that,
Magnitude of charge, [tex]q=3.1\times 10^{-16}\ C[/tex]
Potential difference between two points, [tex]\Delta V=+15\ Volts[/tex]
We have to find the magnitude of work done on that charge. The relationship between the work done and the potential difference is given by :
[tex]\Delta V=\dfrac{W}{q}[/tex]
[tex]W=15\ V\times 3.1\times 10^{-16}[/tex]
[tex]W=4.65\times 10^{-15}\ J[/tex]
or
[tex]W=4.7\times 10^{-15}\ J[/tex]
Hence, the magnitude of work done on the charge is [tex]4.65\times 10^{-15}\ J[/tex]
