Respuesta :
Total ways of choosing two trees = 5C2 = 5!/(2! 3!) = 10
Total ways of choosing one of each = 2*3 = 6
Probability = 6/10 = 0.6 = 60%
Total ways of choosing one of each = 2*3 = 6
Probability = 6/10 = 0.6 = 60%
The probability that he chooses trees of two different types is 0.6 or 60%.
What is probability?
It is defined as the ratio of the number of favorable outcomes to the total number of outcomes in other words the probability is the number that shows the happening of the event.
We have a landscaper who is selecting two trees to plant.
The total number of trees he has = 5
Total ways of choosing the two trees = [tex]_{5}^{}\textrm{C}_2[/tex]
[tex]=\frac{5!}{2!(5-2)!}[/tex]
= 10
Total ways of choosing one of each = [tex]_{3}^{}\textrm{C}_1\times_{2}^{}\textrm{C}_1[/tex]
= 6
So probability:
= [tex]\frac{6}{10}[/tex]
= 0.6 or 60%
Thus, the probability that he chooses trees of two different types is 0.6 or 60%.
Learn more about the probability here:
brainly.com/question/11234923