what is the final speed of a skater who accelerates at a rate of 2.0m/s^2 from rest for 3.5s? Show your work

Okay, so lets look at the equation.

The Skate accelerates at 2.0m/s². This can confuse some people but basically all you need to do is plug in the seconds.

So lets do 1 second. It would be 2.0m/1² which is 2.0m.

Lets do 2 seconds. It would be 2.0m/2² which is 0.5m.

Lets do 3 seconds. It would be 2.0m/3² which is 0.222m

Lets do 3.5 seconds which is about 0.163m.

Add those together and you get 2.885m.

This may be wrong but this is what I got given what you gave (that its seconds squared).

abidemiokin abidemiokin · Answer 2 · 2020-02-01T12:58:08+01:00

Answer: 7.0m/s

Explanation:

Acceleration is defined as the change in velocity of a body with respect to time.

Mathematically, Acceleration = Change in velocity/time

Change in velocity = Final velocity (v) - Initial velocity(u)

Acceleration = Final velocity - Initial velocity/time taken i.e a = v-u/t

Since the body starts from rest, its initial velocity will be zero i.e u = 0m/s

Final velocity/speed = ?

Acceleration = 2.0m/s²

Time taken = 3.5seconds

Substituting this values into the acceleration formula, we have;

2.0 = v - 0/3.5

7.0 = v

This shows that the final speed of the skater will be 7.0m/s