ProPeace
ProPeace
20-02-2015
Mathematics
contestada
[tex]9X^2-12X+4=0[/tex] X=?
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konrad509
konrad509
20-02-2015
[tex]9x^2-12x+4=0\\ (3x-2)^2=0\\ 3x-2=0\\ 3x=2\\ x=\dfrac{2}{3} [/tex]
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ValyRemus
ValyRemus
20-02-2015
[tex]9x^2-12x+4=0[/tex]
[tex](3x)^2-2\cdot 2\cdot3x+2^2=0[/tex]
[tex](3x-2)^2=0, but...(3x-2)^2 \geq 0[/tex] , ∨ x∈R
[tex]So, (3x-2)^2=0[/tex]
[tex]3x-2=0[/tex] ⇒ [tex]3x=2[/tex] ⇒ [tex]\boxed { x= \frac{2}{3} }[/tex]
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