Respuesta :

The value of  [tex]K_{sp}[/tex]  for PbS is [tex]9.0\times10^{-29}[/tex].

Molar solubility (M) is a unit of measurement for a compound's capacity to dissolve in a particular liquid, also known as a solvent. Molar solubility is measured in terms of [tex]\frac{moles}{litre}[/tex] since it is the most moles of a solute that can dissolve in one liter of solvent. The solution is said to be saturated when it can no longer dissolve any more solute and the number of moles dissolved in a liter of solvent equals the molar solubility.

Lead(II) sulfide is a poorly soluble salt compound in water with the following Solubility Equilibrium:

[tex]PbS(s)\Longleftrightarrow Pb^{+2}(aq)+S^{-2} (aq)[/tex]

[tex]K_{sp}=[Pb^{+2}][S^{-2} ][/tex]

The compound dissociates in a 1:1 ratio of ions, therefore the molar Solubility is 's' in water will be :

s=[tex]9.5\times10^{-15}[/tex].

[tex]K_{sp}=s\times s=s^{2}[/tex]

[tex]K_{sp}=(9.5\times10^{-15} )^{2}[/tex]

[tex]K_{sp} =9.0\times10^{-29}[/tex]

Learn more about Solubility.

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