1/S' + 1/S = 1/f
-1/4 +1/S = 1/5
1/v-1/u=1/f
So
1/(-4)-1/u=1/5
So
v=-2.22mm in front of lens as we are getting same sign as that for image i.e negative
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The object of this image will be formed in front of lens with object distance v of -2.22 mm.
1/S' + 1/S = 1/f
-1/4 +1/S = 1/5
S = 20/9 mm = 2.22 mm
1/v-1/u=1/f
So
1/(-4)-1/u=1/5
So
v=-2.22mm in front of lens as we are getting same sign as that for image i.e negative.
For more information on converging lens kindly visit to
https://brainly.com/question/14299912
#SPJ4