consider the genetic map for three loci: a 7 cm b 30cm c 500 progeny were obtained from a cross between abc/abc x abc/abc. in the progeny, 4 abc/abc and 2 abc/abc were observed. how much genetic interference was observed in this cross?

Respuesta :

The value of interference is 43%.

The AbC/ABC and aBc/ABC are double cross over progenies. Because AbC and aBc are produced from heterozygous parent by double cross over.

aBc gametes are produced from aBc/aBc parent.

Observed numbers of double cross overs are: 4+2= 6

Expected numbers of double cross overs are:

Genetic distance between (A-B/100)×(B-C/100) ×Total

=(7/100) ×(30/100) ×500

= 0.07 ×0.30 ×500

= 10.5

Coefficient of coincidence= Observed double cross over /Expected double cross over

= 6/10.5

= 0.57142

Interference= 1-coefficient of coincidence

= 1-0.57

=0.43

Interference in terms of percentage is: 0.43×100

=43%

Therefore, the 43% of interference occurs due to inhibition of cross over at another region due to crossing over at adjacent region.

For such more questions about interference

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