An airplane has an airspeed of 528 mi/hr bearing 25⁰ west of north. The path can be described as a vector v = (528 cos 115⁰) i + (528 sin 115⁰) j
Suppose we have a vector with magnitude v and angle α with the positive x-axis, then the vector can be expressed as its component as:
vx = v cos α
vy = v sin α
or
v = vx i + vy j
v = (v cos α) i + (v sin α) j
In the given problem, the magnitude is 528, while the angle is:
α = 25⁰ west of north = 25⁰ + 90⁰ = 115⁰
Hence,
vx = 528 cos 115⁰
vy = 528 sin 115⁰
v = (528 cos 115⁰) i + (528 sin 115⁰) j
Learn more about vector here:
https://brainly.com/question/25705666
#SPJ4
