a merry-go-round has a radius of 1.2 m and a mass of 116 kg. you may consider the merry-go-round to be a solid disk. a 58 kg student stands on the outer edge of the merry-go-round, 1.2 m from the center (the axis of rotation). it takes 2 s for the merry-go-round and the student to make one revolution. the student then walks radially inward 0.3 m towards the axis of rotation and stands at that point. what is the final angular speed of the merry-go-round?

Respuesta :

The tangential speed v is said to be proportional to the distance r from the center of rotation according to the equation v = r v = r.

The definition of angular momentum (L), with some simplification, is the object's distance from the rotation axis multiplied by the linear momentum: L = r*p or L = mvr. The height of the radar system, h, is fed into the equation d=(2Reh) to determine the radar horizon, where Re is the Earth's radius and d is the radar horizon. The radial distance d can be calculated using the analytic equation given by tan (1 + )/tan (0 + ), where is gaussian noise (sensor position h = 0.1).

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