Rawly has a mass of 79. 0 kg, and he is sledding down a hill that is 29. 5 m tall. As he goes down the hill, his gravitational potential energy is converted into kinetic energy. When he has descended 21. 0 m down the hill, how much kinetic and gravitational potential energy does he have?

Respuesta :

Because of the conservation of energy, the kinetic energy will be 6580.7 J, while the potential energy will be 16258.2 J

Conservation of Energy

Conservation of energy states that energy can not be destroyed nor created but can only be transformed from one form to another.

Given that Rawly has a mass of 79. 0 kg, and he is sledding down a hill that is 29. 5 m tall.

The total energy at the top = maximum P.E

Maximum P.E = mgh

Maximum P.E = 79 × 9.8 ×29.5

Maximum P.E = 22838.9 J = Total energy

As he goes down the hill, his gravitational potential energy is converted into kinetic energy. When he has descended 21. 0 m down the hill, the new P.E that is, gravitational potential energy will be

P.E = mgh

P.E = 79 × 9.8 × 21

P.E = 16258.2 J

Total energy = P.E + K.E

Kinetic energy K.E = Total energy - P.E

K.E = 22838.9 - 16258.2

K.E = 6580.7 J

Therefore, he will have kinetic and gravitational potential energy of 6580.7 J and 16258.2 J respectively.

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