The number of moles of hydrogen (H₂) consumed in the catalytic reduction of 1 mole of 1,3-dibromocyclohexa-1,4-diene is 2 moles.
What is the product of the catalytic reduction of 1,3-dibromocyclohexa-1,4-diene?
The catalytic reduction of 1,3-dibromocyclohexa-1,4-diene involves the addition of hydrogen atoms across the double bond of the 1,3-dibromocyclohexa-1,4-diene molecule.
A 1,3-dibromocyclohexa-1,4-diene molecule has two double bonds in the molecule at the C-1 and C-4 position. The product of the catalytic reduction of 1,3-dibromocyclohexa-1,4-diene is 1,3-dibromocyclohexane.
Hence, two moles of hydrogen molecules, H₂, are added across the two double carbon-to-carbon bonds.
Learn more about carbon-carbon double bonds at: https://brainly.com/question/497851
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