A brick with 30 N weight and dimension 20 x 30 x 30 cm will exert minimum pressure of 333.33 Pa and maximum pressure of 500 Pa.
The relation between force and pressure is given by:
P = F/ A
Where:
P = pressure
F = force
A = area perpendicular to the applied force.
In the given problem, the dimension of the brick is 20 cm x 30 cm x 30 cm.
Hence,
if the brick is positioned horizontally, the area perpendicular to the gravity force (weight) is 30 x 30 = 900 cm² = 0.09 m²
if the brick is positioned vertically, the area perpendicular to the gravity force (weight) is 20 x 30 = 600 cm² = = 0.06 m²
Therefore,
minimum pressure = 30 N / 0.09 = 333,3 N/m²
maximum pressure = 30 N / 0.06 = 500 N/m²
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