7. The equation 8x – 4y = 5 is dilated by a scale factor of 8 centered at the origin. What is the new slope and

y-intercept after dilation? (3 points)

One formula for figuring out a line's equation is the slope-intercept formula.
A line with slope m and a y-intercept of b has a slope-intercept formula of y = mx + b. Any point on the line is (x, y) in this case.

The equation of given line 8x-4y=5 and it is dilated by a scale factor of 8 centered at the origin.

When x=0, y=?

8x - 4y = 5

8(0) - 4y = 5

y = - 5/4

When y=0, x=?

8x - 4y = 5

8x - 4(0) = 5

x = 5/8

we get points A( 0, -5/4) , B(5/4 , 0)

For point A:

Distance of point A(0, -5/4 ) from origin is ( -5/4) unit in x-direction and zero ( -5/4) unit in y-direction.

After scaled by factor of 8, the distance will multipy by 8 and new location is A'( 0, -10)

For point B:

Distance of point B( 5/8,0) from origin is (5/8) unit in x-direction and zero unit in y-direction.

After scaled by factor of 8, the distance will multipy by 8 and new location is B'( 5,0)

Equation of new line

Points A'(0, -10 ) and B'( 5,0) make a new line

The equation of given as

y - y₁/x - x₁ = y₂ - y₁/x₂ - x₁

y - ( -10)/x - 0 = 0 - (-10)/5 - 0

y + 10/x = 2

y + 10 = 2x

y = 2x - 10

Now, Comparing with the equation of the line : y=mx + c

Where m=slope and c is the y-intercept

We get, Slope m=2 and y-intercept c=(-10)

Learn more about Slope-Intercept Formula

brainly.com/question/16664039

#SPJ4

Respuesta :