51.9% is the mass percent of barium in the sample
The molar mass of BaSO₄ = 233.3 g/mol
Barium molecular weight = 137.3 g/mol
%Ba in BaSO₄ = 137.3/233.3 × 100 = 58.5%
i.e; the mass of Ba²⁺ ions in 0.764 g of BaSO₄
58.85% of 0.764 = 0.439 g
% of Ba²⁺ ions in the sample = 0.439/0.846 × 100 = 51.9%
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