The number of dimes that Paula had in the purse is 0 dimes .
In the question ,
it is given that ,
the average value of all the pennies , nickels , dimes and quarters = 20 cents .
let the total value (in cents )that Paula has originally be "v" ,
let the number of coin she had be "n" ,
that is , v/n = 20
So ,v = 20n
if she had 1 more quarter means the value of all the coins = v + 25
and number of coins becomes = n + 1
the new average is given as 21,
that means ,
(v + 25)/(n + 1) = 21
v + 25 = 21(n+ 1)
v + 25 = 21n + 21
Substituting the value of v = 20n , we get
20n + 25 = 21n + 21
21n - 20n = 25 - 21
n = 4
and v = 20(4) = 80
and the only way that Paula can satisfy this rule is, if she had 3 quarters and 1 nickel in her purse.
Therefore , The number of dimes that Paula had in the purse is 0 dimes .
The given question is incomplete , the complete question is
The average value of all the pennies, nickels, dimes, and quarters in Paula's purse is 20 cents. if she had one more quarter, the average would be 21 cents. How many dimes does she have in her purse ?
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