contestada

a 35.0-ml sample of 0.20 m lioh is titrated with 0.25 m hcl. what is the ph of the solution after 23.0 ml of hcl have been added to the base? provide your answer rounded to 2 decimal digits

Respuesta :

The ph of the solution after 23.0 ml of HCl have been added to the base is 3.88 M.

Concentration is the abundance of a constituent divided by way of the overall volume of an aggregate. several sorts of mathematical descriptions may be outstanding: mass concentration, molar concentration, variety concentration, and extent awareness.

Calculation:-

Given,

C₁ = 0. 2 M

V₁ =  35. 0 ml = 0.035 L

C₂ = 0. 25 M

V₂ =  253. 0 ml = 0.023 L

C₁V₁ + nC₂V₂ = C × total volume

0. 255 ×  0.035 + 2×0. 328 × 0.045 L = C × 0.08

C = (0.0089 + 0.0296) / 0.08

   = 0.0385 / 0.08

  = 0.48 M

Calculation:-

Normality of acid                                                normality of base

= nMV                                                                        nMV

= 1 × 0. 20 × 0.035 L                                               1 ×  0. 25 ×0.023 L

= 7 × 10⁻³                                                             = 5.75 × 10⁻³

the overall acid will be high

net concentration = 7 × 10⁻³ - 5.75 × 10⁻³

 = 1.25 × 10⁻³

pH = -log[1.25 × 10⁻⁴]

       = 4 - log 1.25

       = 4 - 0.12

      = 3.88

The concentration of a substance is the quantity of solute found in a given amount of solution. Concentrations are normally expressed in terms of molarity, defined because of the variety of moles of solute in 1 L of solution.

The Concentration of an answer is a measure of the quantity of solute that has been dissolved in a given amount of solvent or solution. A concentrated answer is one that has a rather huge quantity of dissolved solute.

Learn more about concentration here:-https://brainly.com/question/26255204

#SPJ4

ACCESS MORE
ACCESS MORE
ACCESS MORE
ACCESS MORE