Answer:0.28975 moles of nitrogen are formed .
Explanation:
[tex]4KNO_3(s)\rightarrow 2K_2O(s)+2N_2(g)+5O_2(g)[/tex]
Number of moles of [tex]KNO_3=\frac{\text{Mass of the}KNO_3}{\text{Molar mass of the}KNO_3}=\frac{58.6 g}{101.11 g/mol}=0.5795 moles[/tex]
According to reaction , 4 mol of [tex]KNO_3[/tex] produces 2 moles of [tex]N_2[/tex] gas.
Then,0.5795 moles of [tex]KNO_3[/tex] will produce=[tex]\frac{2}{4}\times 0.5795 [/tex] moles of [tex]N_2[/tex] gas:
[tex]\frac{2}{4}\times 0.5795=0.28975 moles[/tex]
0.28975 moles of nitrogen are formed.
