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Acetic acid is a polar molecule and can form hydrogen bonds with water molecules. therefore, it has high solubility in water. yet acetic acid is also soluble in benzene (c6h6, a nonpolar solvent that lacks the ability to form hydrogen bonds. a solution of 3.8g of ch3cooh in 80g of c6h6 has a freezing point of 3.5 degrees celsius. calculate the molar mass of the solute and suggest what it's structure might be.

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MissPhiladelphia

Colligative properties calculations are used for this type of problem. Calculations are as follows:

Look up the freezing point of benzene, then delta T = f.p.=3.5 = Kf*m 
Solve for molality. 

molality = moles/kg solvent 
Solve for moles. 

moles acetic acid = grams acetic acid/molar mass acetic acid 
Solve for molar mass. You would expect to find 60 for the molar mass CH3COOH.

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