Respuesta :
Just use unit analysis, but you'll have to balance the equation first
3H2-> 2NH3 (Other products and reactants omitted)
3.64 g/ 2 (g/mol) * 2/3 * 17= 20.6 g of NH3
3H2-> 2NH3 (Other products and reactants omitted)
3.64 g/ 2 (g/mol) * 2/3 * 17= 20.6 g of NH3
The number of grams of [tex]NH_3[/tex] that could be produced is 20.6g.
Given that,
- There are 3.64g of [tex]H_2[/tex].
- There is the chemical equation of [tex]N_2(g) +3H_2(g) \rightarrow 2NH_3 (g)[/tex].
Based on the above information, the calculation is as follows:
N2(g) +3H2(g)-> 2NH3 (g)
28g 6g 34g
Now
[tex]6gH_2 \rightarrow 34g NH_3[/tex]
So for 3.64g should be
[tex]= 34\times 3.6\div6[/tex]
= 20.6g
Therefore we can conclude that the number of grams of [tex]NH_3[/tex] that could be produced is 20.6g.
Learn more: brainly.com/question/943897
