air is expanded from 1000 kpa and 600°c at the inlet of a steady-flow turbine to 100 kpa and 200°c at the outlet. the inlet area and velocity are 0.1 m2 and 30 m/s, respectively, and the outlet velocity is 10.5 m/s. determine the mass flow rate and outlet area. the gas constant of air is r

Respuesta :

The mass flow rate is given as 11 .973 kg / seconds

The outlet area is given as 1.548 m³

How to solve for the mass flow rate

we have

1000 / 0.287 x (600 + 273)

= 3.991 kg/m3

The mass flow rate = 3.991 x 0.1 x 30

= 11 .973 kg / seconds

Next we have to solve for the outlet area

100 / 0.287 x (200 + 273)

= 0.7633 kg/m³

The outlet area = 11.973 / 0.7366 x 10.5

= 11.973 / 7.7343

= 1.548

In conclusion the calculations are as follows

mass flow rate = 11.973

the outlet area is solve to be 1.548

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