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Question ID: 97725The movement of the progress bar may be uneven because questions can be worth more or less (including zero) depending on your answer.A semi-circle sits on top of a rectangle to form the figure below. Find its area and perimeter. Use 3.14 for Te.3 in4 inA = 37.12 square inches, Pz 16.28 inchesA = 18.28 square inches, P 22.56 inchesA = 37.12 square inches, P = 22.56 inchesA ~ 18.28 square inches, P 16.28 inches

Question ID 97725The movement of the progress bar may be uneven because questions can be worth more or less including zero depending on your answerA semicircle class=

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Solution

For this case we can find the area as the sum of the rectangle and the semicircle so we have this:

A1= 3in * 4in= 12 in^2

A2 = (pi/2) *(2in)^2 = 6.28 in^2

then the total area is:

A= A1+ A2= 12+ 6.28 in^2 = 18.28 in^2

And then the perimeter similarly we have:

P= 2*4 in + 2*3in + 2pi*(4in/2) = 8+ 6+ 12.56 in= 26.56in

Then the final answer is:

Area ~18.28 in^2 and Perimeter ~26.56 in

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