The mass (in grams) of MgSO₄ That should be used is 1.26 g
How to determine the mass of MgSO₄
We'll begin by writing the balanced equation for the reaction. This is given below:
MgSO₄ + 2HCl —> MgCl₂ + H₂SO₄
- Molar mass of MgSO₄ = 24 + 32 + (16 × 4) = 120 g/mol
- Mass of MgSO₄ from the balanced equation = 1 × 120 = 120 g
- Molar mass of MgCl₂ = 24 + (35.5 × 2) = 95 g/mol
- Mass of MgCl₂ from the balanced equation = 1 × 95 = 95 g
Finally, we shall determine the mass of MgSO₄ needed for the reaction as follow:
From the balanced equation above,
95 g of MgCl₂ were produced from 120 g of MgSO₄
Therefore,
1 g of MgCl₂ will be produce from = (1 × 120) / 95 = 1.26 g of MgSO₄
Thus, the mass of MgSO₄ needed is 1.26 g
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