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A 2kg mass hangs at the end of spring whose constant is k=800n/m the mass is displaced a distance of 10cm and then released what is the velocity of the instant the displacement is x=+6cm?

Respuesta :

Answer:

Let x = A cos ω t      when ω t = 0, x = A = .1 m

x = .1 cos ω t

cos ω t = .06 / .1 = .6       when x = .06

ω t = 53.1 deg        at a displacement of .06

v = -ω A sin ω t      speed of particle

ω = (k / m)^1/2 = (800/2)^1/2 = 20

v = 20/s * .1 m sin 53.1 = 1.60 m/s

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