Segments AD and BC intersect at point O.
Prove that AC = BD,
m∠ABC=m∠BAD.

Since both triangles are congruent, then we can conclude that AC = BD by Angle - Side - Angle congruence theorem.
In ΔOAC and ΔODB, we have the following observations
CO = DO because it is shown that they are congruent
∠AOC = ∠BOD because vertical angles are congruent
∠ACO = ∠BDO because we are given that they are congruent
Now, the congruency theorem that we can use here is ASA which means Angle - Side - Angle. This implies that 2 corresponding angles and the included side are congruent.
If any two angles and the side included between the angles of one triangle are equivalent to the corresponding two angles and side included between the angles of the second triangle, then the two triangles are said to be congruent by Angle - Side - Angle congruence theorem.
Since both triangles are congruent, then we can conclude that AC = BD by Angle - Side - Angle congruence theorem.
Read more about Congruent Angles at; https://brainly.com/question/24913488
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