The maximum number of cubical boxes of side 1 feet that can be placed in a rectangular closet of length 6 feet, height 9 feet and breadth 5 feet is 270 boxes. Maximum number of boxes that can be placed along the length, height and breadth will be 168 boxes, 198 boxes and 150 boxes respectively.
Since the cube shaped boxes of length 1 feet are to be placed in the rectangular closet, the maximum number of boxes that will fit completely would be given as a comparison of volume of rectangular closet being equal to product of number of boxes and volume of 1 cubical box.
Volume of rectangular closet = Number of boxes * Volume of 1 cubical box
6 * 9 * 5 = n * (1*1*1)
Therefore, n = 270 boxes.
To calculate maximum number of boxes that will fit along the length would be calculated as product of length and breadth along 2 faces of closet and length and height along another 2 faces of closet.
Thus, [(9*6) + (9*6) + (6*5) + (6*5)] = 168 boxes along the length.
Similarly, to calculate maximum number of boxes that will fit along the height would be calculated as product of height and breadth along 2 faces of closet and length and height along another 2 faces of closet.
Thus, [(9*6) + (9*6) + (9*5) + (9*5)] = 198 boxes along the height
Similarly, to calculate maximum number of boxes that will fit along the breadth would be calculated as product of height and breadth along 2 faces of closet and length and breadth along another 2 faces of closet.
Thus, [(5*6) + (5*6) + (9*5) + (9*5)] = 150 boxes along the breadth.
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