A stone with a mass of 10 kg sits on the ground. Gravity acts on the stone at a rate of 9.8 m/s2. What is the normal force
acting on the stone, keeping it at rest? (1 point)
O 1.02 N
O 9.8 N
O 10 N
O98 N

Respuesta :

Answer:

Fn = m x g

Fn = normal force

m = mass of the stone

g = gravitational force acting on the stone.


therefore, fn=m x g = 10kg x 9.8m/s2 = 98 kgm/s2 or 98 N. Which is the same as 098 N.

Explanation:

A stone with a mass of 10 kg sits on the ground. The normal force acting on the stone, keeping it at rest, is 98 N. The correct option is D.

What is force?

A force is a power that changes the position of an object. This results in the action or movement of any object. Force is calculated in Newton. The force can be calculated by multiplying the mass by acceleration.

Given, the mass of the stone is 10 kg

The gravitational force act at the rate of 9.8 m/s²

The formula is

Force  = mass x gravitational rate

Fn = normal force

m = mass of the stone

g = gravitational force acting on the stone

So, fn = m x g

10kg x 9.8 m/s²

98 kg m/s²or 98 N

Therefore, the normal force acting on the stone, keeping it at rest, is 98 N. The correct option is D.

To learn more about force, refer to the link:

https://brainly.com/question/3884655

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