Apartment traveling on a straight road at 15.0m/s accelerate uniformly to a speed of 21.0m/s in 12.0 seconds the total distance traveled by the car in this 12.0 seconds time interval is

Respuesta :

By using uniform motion, the distance traveled by the car is 216 m.

We need to know about the uniform motion to solve this problem. The uniform motion is an object's motion under acceleration. It should follow the rule

vt = vo + a . t

vt² = vo² + 2a . s

s = vo . t + 1/2 . a . t²

where vt is final velocity, vo is initial velocity, a is acceleration, t is time and s is displacement.

From the question above, we know that

vo = 15 m/s

vt = 21 m/s

t = 12 s

Find the acceleration

vt = vo + a . t

21 = 15 + a . 12

12a = 6

a = 0.5 m/s²

By using the third equation, we can calculate the distance

s = vo . t + 1/2 . a . t²

s = 15 . 12 + 1/2 . 0.5 . 12²

s = 180 + 36

s = 216 m

Find more on uniform motion at: https://brainly.com/question/28040370

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