well, let's take a peek, hmmm 10000 bucks at 3% over 6 years hmmm
[tex]~~~~~~ \textit{Simple Interest Earned Amount} \\\\ A=P(1+rt)\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill & \$10000\\ r=rate\to 3\%\to \frac{3}{100}\dotfill &0.03\\ t=years\dotfill &6 \end{cases} \\\\\\ A=10000[1+(0.03)(6)] \implies \boxed{A = 11800}~\hfill \cfrac{\stackrel{total}{11800}}{\underset{months}{72}}\approx \underset{per~month}{163.89}[/tex]
