The intensity of sunlight at the Earth's distance from the Sun is 1370 W/m². Assume the Earth absorbs all the sunlight incident upon it. (b) Explain how this force compares with the Sun's gravitational attraction

Respuesta :

Comparing these two values, Fgav is much greater than Fr.

First, calculate the force produced by the radiation pressure:

The radiation pressure produces a force equal to,

Fr=pr(πRe2)

=(I/c) ( πRe2)

Given that

I= Intensity of sun = 1370 W/m²

c = speed of light = 2.998×108m/s

Re = Radius of the earth=  6.37×106m

Ms= mass of sun = 2.0×1030kg

Me= mass of earth = 5.98×1024kg

des2 = distance of earth and sun apart =1.5×1011m

Substituting the given values according to the question

Fr= π (1.37 × 103 kW/m2) (6.37×106m)2/2.998×108m/s

=6.0×108N

(b) The gravitational pull of the Sun on the Earth is,

Fgav= GMsMe/ des2

putting values according to question

Fgav= (6.67×10−11 N⋅m2/kg2) (2.0×1030kg) (5.98×1024kg) / (1.5×1011m)2

=3.6×1022N.

Comparing these two values, it is obvious that Fgav is much greater than Fr.

To learn more about gravitational force. Click, https://brainly.com/question/12528243

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