dannaalfonso12p0nafu
contestada

Draw AABC with vertices at A(1,6), B(1, 1) and C(5, 1). In this triangle, AB²+ BC² = AC².
Next, use the GeoGebra tools to draw ADEF such that AB = DE, m/E = 90°, and
EF = BC.
Paste a picture of your drawing in the answer box.

Draw AABC with vertices at A16 B1 1 and C5 1 In this triangle AB BC AC Next use the GeoGebra tools to draw ADEF such that AB DE mE 90 and EF BC Paste a picture class=

Respuesta :

The picture of the triangle ΔDEF is attached below.

A triangle can be defined as a basic polygon which has 3 sides.

  • The sum of all the interior angles of a triangle is given by 180°.
  • The area of any triangle is calculated by [tex]\frac{1}{2}[/tex] × base × height.
  • In a right-angled triangle the side opposite the largest angle which is 90° is called the hypotenuse.
  • Pythagoras' theorem states that the sum of the squares of the legs of aright-angles triangle is equal to the square of the hypotenuse of the triangle.

In the given ΔABC we see that AC is the hypotenuse and the two sides AB and AC are the legs of the triangle.

m∠B=90°

The ΔDEF is drawn such that m∠E=90° and AB=DE and EF=BC .

Therefore we can say that the two triangles are congruent by SAS axiom of congruency.

To learn more about triangle visit:

https://brainly.com/question/2773823

#SPJ9

Ver imagen rafikiedu08
ACCESS MORE
ACCESS MORE
ACCESS MORE
ACCESS MORE

Otras preguntas