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Because of increasing evidence of damage to the ozone layer, chlorofluorocarbon (CFC) production was banned in 1996. However, many older cars still have air conditioners that use CFC-12 (CF2Cl2). These air conditioners are recharged from stockpiled supplies of CFC-12. Suppose that 100 million automobiles each contain 1.0 kg of CFC-12 and leak 24 % of their CFC-12 into the atmosphere per year.

How much chlorine, in kg , is added to the atmosphere each year due to these air conditioners?

Respuesta :

The mass of chlorine is 9.9 * 10^6 kg.

Total mass of CFC = M(CFC) * number of cars = 1.0 kg * 1.00 * 10^8

= 1.00 * 10^8 kg

Mass of the leaked CFC ;

% leaked = m(leaked) *100 / m(total)

m(leaked) = o.24 * 1.00 * 10^8 kg

m(leaked) = 2.4 * 10^6 kg

Now no. of moles of CFC:

n(CFC) = m(CFC) / MM(CFC) = 2.4 * 10^9 g / 170.92 g/mol = 0.014 * 10^9 mol

= 1.4 * 10^7 mol

No. of moles of chlorine ;

n(Cl) = n(CFC)*2

= 1.4  * 10^7 mol *2

= 2.8 * 10^7 mol

Now at last the mass of the chlorine :

m(Cl) = n(Cl) * MM(Cl)

= 2.8 * 10^7 mol * 35.453 g/mol

= 99.2 * 10^10 g

Mass of Cl = 9.9 * 10^6 Kg

To know more about chlorofluorocarbon (CFC) here :

https://brainly.com/question/14464840?referrer=searchResults

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