A scientist repeats the Millikan oil drop experiment in a different galaxy and the charge on the drops is measured in a unit called the electrino (el). The scientist obtains data for four drops. Drop Calculated charge (el) A) 5.52×10−14 el. B) 2.30×10−14 el. C) 3.22×10−14 el D) 2.76×10-14 el. Given the results of the scientist's experiment, determine the charge on an electron in electrinos.

We need a value that multiplied by different integers gives us the values of charges given. For this we grab the smallest charge, divide it by other integers and multiply it by ones given at the starting to try to get the other charges. We should expect other results that were never measured also (could be), for now let's ignore all the 10^-14 and the units.

We start with 2.76.May be this is the elemental charge and we would only need to multiply by other integers to obtain the rest of the charges. Let us see now :

2(2.30) = 4.6 we can't get 2.76, we will try with next possibility,

2(2.30/2) = 2.30, obviously,

3(2.30/2) = 3.45 could be, we couldn't get 2.76 so now move forward

2(2.30/3) = 1.5 could be,

3(2.30/3) = 2.30 obviously, we couldn't get 2.76 so now move forward

2(2.30/4) = 1.15 could be,

3(2.30/4) = 1.72 could be,

4(2.30/4) = 2.3 obviously, we couldn't get 2.76 so now move forward

5(2.30/4) = 2.87 could be, we couldn't get 2.76 so now move forward

2(2.30/5) = 0.92 could be,

3(2.30/5) = 2.30 obviously , we couldn't get 2.76 so now move forward

6(2.30/5) = 2.76 we get the value two more left now we move forward,

7(2.30/5) = 3.22 we get the value now one more left, so we move forward,

8(2.30/5) = 3.68 could be,

9(2.30/5) = 4.14 could be,

10(2.30/5) = 4.6 could be,

11(2.30/5) = 5.06 could be,

12(2.30/5) = 5.52 done

since (2.30 / 5) = 0.46 , the elemental charge could be 0.46 * 10^-14 electron (any value obtained by dividing this over any integer could also be the elemental charge)

To know more about Millikans drop experiment here :

https://brainly.com/question/25831090?referrer=searchResults

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