Using relations in a right triangle, it is found that the length of y is given by:
[tex]y = 2\sqrt{6}[/tex]
What are the relations in a right triangle?
The relations in a right triangle are given as follows:
- The sine of an angle is given by the length of the opposite side to the angle divided by the length of the hypotenuse.
- The cosine of an angle is given by the length of the adjacent side to the angle divided by the length of the hypotenuse.
- The tangent of an angle is given by the length of the opposite side to the angle divided by the length of the adjacent side to the angle.
The hypotenuse of both triangles is found as follows:
sin(60º) = 6/x.
[tex]\frac{\sqrt{3}}{2} = \frac{6}{x}[/tex]
[tex]x = \frac{12}{\sqrt{3}} \times \frac{\sqrt{3}}{\sqrt{3}}[/tex]
[tex]x = 4\sqrt{3}[/tex]
Hence length y is found as follows:
[tex]\cos{45^\circ} = \frac{y}{4\sqrt{3}}[/tex]
[tex]\frac{\sqrt{2}}{2} = \frac{y}{4\sqrt{3}}[/tex]
[tex]2y = 4\sqrt{6}[/tex]
[tex]y = 2\sqrt{6}[/tex]
More can be learned about relations in a right triangle at https://brainly.com/question/26396675
#SPJ1
