The final temperature of the gas that expands from a volume of 22.4 l at 278k to a volume of 38.3 l will be 475 K.
The volume as well as Kelvin temperature will be directly proportional whenever the pressure on even a sample of such a dry gas remains held constant. PV = k would be the law's equation.
Charle's law give the relation between the temperature and volume is shown as:
[tex]V_{1} / T_{1} = V_{2} / T_{2}[/tex]
where. V is volume and T is temperature.
Given data :
[tex]V_{1} =22.4 l\\V_{2} = 38.3 l\\T_{1} = 278 K\\T_{2} = ?[/tex]
Put the value of given data in above equation.
22.4 l / 38.3 l = 278k / [tex]T_{2}[/tex]
[tex]T_{2}[/tex] = 475 K.
Therefore, the final temperature will be 475 K.
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