There are 4 L of a 0.75 m solution of ca(no3)2 are needed if 3.0 moles of ca(no3)2 are required
The word molecule is the root of the word mole. It has nothing to do with the so-called mole animal. Most frequently, the mole is employed to convert between quantities of atoms but also molecules as well as the gram mass unit.
Volume can be determined by the formula:
n = m × V
n = number of mole
m = molarity
V = volume
Given data:
m = 0.75 m
n = 3 mole
V = ?
Put the value of given data in above equation.
V = n /m
V = 3 / 0.75
V = 4 L.
Therefore, there are 4 L of a 0.75 m solution of [tex]Ca(NO_{3} )_{2}[/tex] are needed if 3.0 moles of [tex]Ca(NO_{3} )_{2}[/tex] are required.
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