Respuesta :
The area of the triangle is 94.9 square inches
For given question,
We have been given triangle RST has sides measuring 22 inches and 13 inches and a perimeter of 50 inches.
Let x be the third side of ΔRST
⇒ 22 + 13 + x = 50
⇒ x = 50 - 35
⇒ x = 15
Let s = sum of three sides of the triangle / 2
s = (22 + 13 + 15)/2
s = 25
Now using the formula for the area of the triangle,
A = √[s × (s-a) × (s-b) × (s-c)]
Let a = 22 inches, b = 13 inches, c = 15 inches
Substituting the values,
⇒ A = √[25 × (25 - 22) × (25 - 13) × (25 - 15)]
⇒ A = √(25 × 3 × 12 × 10)
⇒ A = √9000
⇒ A = 94.9 square inches
Therefore, the area of the triangle is 94.9 square inches
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The area of triangle rst which have sides 22 inches and 13 inches with perimeter 50 inches is 95 square inches.
We are given that the two sides of the triangle rst are 22 inches and 13 inches respectively. Also perimeter of the triangle rst is 50 inches.
We have to find the area of triangle to the nearest square inches.
Let the third side of the triangle rst be x.
Hence,
22 + 13 + x = 50 inch
35 + x = 50 inch
x = 50 - 35
x = 15 inches
Hence, the third side of the triangle is 15 inches.
We will use the Heron's formula here to find the area of the triangle.
Heron's formula = [tex]\sqrt{s(s-a)(s-b)(s-c)}[/tex]
Here,
s = Semi- perimeter
a, b, and c are sides of the triangle.
Hence,
[tex]s=\frac{50}{2} \\\\s=25 inches[/tex]
a = 22 inches
b = 13 inches
c = 15 inches
Hence,
Area of the triangle rst = [tex]\sqrt{25(25-22)(25-13)(25-15)}\\\\ \sqrt{25(3)(12)(10)} =\sqrt{5*5*3*3*2*2*5*2}=5*3*2\sqrt{5*2}=30\sqrt{10}[/tex]
We know that,
[tex]\sqrt{10}[/tex] ≈ 3.162277
Hence,
[tex]\sqrt{10} * 30[/tex] ≈ 94.86831 ≈ 95 square inches.
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