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What is brewster's angle for light traveling in vacuum and reflecting off a piece of glass having a refractive index of 1.52?

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The Brewster's angle for light traveling in vacuum and reflecting off a piece of glass having a refractive index of 1.52 is 56.7 degrees.

Brewster's angle is the angle of incidence at which light with a particular polarization is perfectly transmitted through a transparent dielectric surface, with no reflection.

When unpolarized light is incident at this angle, the light that is reflecting from the surface is therefore perfectly polarized.

The special angle of incidence that produces a 90 degrees angle between the reflected and refracted ray is called the Brewster angle, ∅p.

Formula for Brewster's angle: tan(∅) = μ

Given, The refractive index is μ. =1.52

By given the above relation,

tan∅ = μ

∅ = [tex]tan^{-1}[/tex](μ)

∅ = [tex]tan^{-1}[/tex](1.52)

∅ = 56.7°

To learn more about Brewster's angle here

brainly.com/question/17156891

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