The maximum number of 120-pound packages that the helicopter can carry per trip = 5
The correct answer is an option (C)
For given question,
Let x be the number of 100-pound packages and y be the number of 120-pound packages.
For each delivery trip, the helicopter must carry at least 10 packages.
So we get an inequality,
x + y ≥ 10 ....................(1)
The total weight of the packages can be at most 1,100 pounds.
So we get an inequality,
100x + 120y ≤ 1100 ...................(2)
From (1),
x = 10 - y
Substitute above value of x in inequality (2)
⇒ 100x + 120y ≤ 1100
⇒ 10x + 12y ≤ 110
⇒ 5x + 6y ≤ 55
⇒ 5(10 - y) + 6y ≤ 55
⇒ 50 - 5y + 6y ≤ 55
⇒ y ≤ 5
Therefore, the maximum number of 120-pound packages that the helicopter can carry per trip = 5
The correct answer is an option (C)
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