A gas with pressure of 5.0 atm is compressed at constant temperature from 10.0 L to 2.0 L then the pressure of the gas after it is compressed is 25 atm .
Calculation ,
Formula used : [tex]P_{1} V_{1} =P_{2} V_2}[/tex]
Given initial pressure [tex]P_{1}[/tex] = 5 atm
given initial volume [tex]V_{1}[/tex] = 10 L
final volume [tex]V_2}[/tex] = 2 L
final pressure [tex]P_{2}[/tex] = ?
Put the value of initial pressure , initial volume and final volume in equation ( i ) we get the pressure of the gas after it is compressed .
5 atm × 10 L = [tex]P_{2}[/tex] × 2 L
[tex]P_{2}[/tex]= 5 atm ×10 L / 2 L = 25 atm
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