Answer:
[tex]\sf \dfrac{49}{4}[/tex]
Step-by-step explanation:
[tex]\sf \dfrac{a^m}{a^n} =a^{m-n}[/tex]
[tex]\sf 4^{x-1}=\dfrac{4^x}{4^1}[/tex]
Write the expression 4ˣ with base 2.
We know that 4 = 2².
[tex]\sf \dfrac{4^x}{4}=\dfrac{2^{2x}}{4}\\\\[/tex]
[tex]\sf= \dfrac{(2^x)^2}{4}\\\\\ = \dfrac{7^2}{4}\\\\=\dfrac{49}{4}[/tex]